JavaScript函数重载机制解析：为何同名函数会相互覆盖

<pre name="code" class="html">function sum(num1,num2) 
{ 
return num1 +num2; 
} 

alert(sum(10,10)); //20 
var other = sum; 
alert(other(10,10)); //20 
sum = null; 
alert(other(10,10)); //20

function sum(num1) 
{ 
return num1 +100; 
} 
function sum(num1) 
{ 
return num1 +200; 
} 
alert(sum(200)); //400

function sum(num1) 
{ 
return num1 +100; 
} 
sum = function(num1) 
{ 
return num1 +200; 
} 
alert(sum(200)); //400